document.write( "Question 1076552: How are the steps to find the coordinates of the vertex for the parabola defined by the given quadratic function:
\n" ); document.write( "2(x-3)^2+1
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Algebra.Com's Answer #691244 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"2%28x-3%29%5E2%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "Vertex occurs in the exact middle of the roots. You can solve for \"2%28x-3%29%5E2%2B1=0\" and then the average of the roots is the x value for the vertex... but since your function is already given in standard form, the vertex is (3,1).\r
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\n" ); document.write( "\n" ); document.write( "The vertex for \"y=a%28x-h%29%5E2%2Bk\" is the point (h,k).
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