document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1076600>Question 1076600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a gas has a volume of <BR>\n" );
document.write( "250 cubic inches under a pressure of <BR>\n" );
document.write( "4 pounds per square inch, what will be its volume if the pressure is increased to 20 pounds per square inch? (Round off your answer to the nearest cubic inch.)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691240 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a gas has a volume of <BR>\n" );
document.write( "250 cubic inches under a pressure of <BR>\n" );
document.write( "4 pounds per square inch, what will be its volume if the pressure is increased to 20 pounds per square inch? (Round off your answer to the nearest cubic inch.) <BR>\n" );
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document.write( "P*V = k<BR>\n" );
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document.write( "5x the pressure --> 1/5 times the volume (using absolute pressure). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );