document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1076579>Question 1076579</A>: <I><SPAN STYLE=\"word-break: break-all;\">  In an alloy of 150 pounds of zinc and copper, there are 100 pounds of copper. How much copper must be added so that the alloy may be 10% zinc?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691196 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In an alloy of 150 pounds of zinc and copper, there are 100 pounds of copper. How much copper must be added so that the alloy may be 10% zinc?<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "zinc + zinc = zinc<BR>\n" );
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document.write( "(1/3)150 + 0*x = 0.10(150+x)<BR>\n" );
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document.write( "50 + 0 = 15 + 0.1x<BR>\n" );
document.write( "35 = 0.1x<BR>\n" );
document.write( "x = 350 lb (amt of copper to add)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );