document.write( "Question 1076464: The sum of three numbers is 91 the first number is nine more than the second the third number is two times the first what are the numbers \n" ); document.write( "
Algebra.Com's Answer #691129 by ankor@dixie-net.com(22740)\"\" \"About 
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The sum of three numbers is 9
\n" ); document.write( "a + b + c = 91
\n" ); document.write( " the first number is nine more than the second
\n" ); document.write( "a = b + 9
\n" ); document.write( "or
\n" ); document.write( "b = a - 9
\n" ); document.write( " the third number is two times the first
\n" ); document.write( "c = 2a
\n" ); document.write( " what are the numbers
\n" ); document.write( "Using the first equation, replace b with (a - 9); replace c with 2a
\n" ); document.write( "a + (a-9) + 2a = 91
\n" ); document.write( "4a = 91 + 9
\n" ); document.write( "4a = 100
\n" ); document.write( " a = 25 is the first number
\n" ); document.write( "then
\n" ); document.write( "b = 25 - 9
\n" ); document.write( "b = 16 is the 2nd number
\n" ); document.write( "and
\n" ); document.write( "c = 2(25)
\n" ); document.write( "c = 50 is the 3rd number
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if that checks out
\n" ); document.write( "25 + 16 + 50 = 91 \n" ); document.write( "
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