document.write( "Question 1069486: Paul has a son named David. The sum of their ages is 84. After three years, Paul will be twice as old as David. What are their ages now? \n" ); document.write( "
Algebra.Com's Answer #691125 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! Let David be d. Then Paul is 84-d. So: \n" ); document.write( "2(d+3)=84-d+3 \n" ); document.write( "2d+6=87-d \n" ); document.write( "3d=81 \n" ); document.write( "d=27 \n" ); document.write( "David is 27; Paul is 57. ☺☺☺☺ \n" ); document.write( " |