document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1074396>Question 1074396</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The RSM Seed Company sells seeds for the Rare Rose, which blooms every 12 years; the Seldom Sunflower, which blooms every 7 years; and the Miracle Magnolia, which blooms every 50 years. If all three plants bloom in 2016, in what year will all three of them bloom again the next time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691117 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This problem needs the least common multiple of 7, 12, and 50. So, factoring each, we get:<BR>\n" );
document.write( "7=7x1<BR>\n" );
document.write( "12=2x2x3<BR>\n" );
document.write( "50=2x5x5<BR>\n" );
document.write( "So, the least multiple is 2x2x3x5x5x7, or 2100. So, 2016+2100= the year 4116 as the next time all three will bloom in the same year. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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