document.write( "Question 1076486: The perimeter of a rectangle is 234ft. When its length is doubled, the perimeter increases by 58ft.\r
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document.write( "Use elimination to determine the dimensions of the rectangle. \n" );
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Algebra.Com's Answer #691110 by jorel1380(3719) You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "2L+2W=234 \n" ); document.write( "2(2L)+2W=234+58=292 \n" ); document.write( "4L+2W=292 \n" ); document.write( "2L+2W=234 \n" ); document.write( "2L=58 \n" ); document.write( "L=29 \n" ); document.write( "W=88 \n" ); document.write( "The dimensions of the rectangle are 29X88 ft. ☺☺☺☺ \n" ); document.write( " |