document.write( "Question 1076500: A person wishes to build a rectangular fence that will enclose an area of 317 square feet. The width
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document.write( "of the fence is to be 3 feet less than twice its length. Set up and solve an algebraic equation to find the
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document.write( "dimensions of the fence to the nearest tenth of
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document.write( "a foot. \n" );
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Algebra.Com's Answer #691106 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! length is x \n" ); document.write( "width is 2x-3 \n" ); document.write( "x(2x-3)=317 \n" ); document.write( "2x^2-3x-317=0 \n" ); document.write( "x=(1/4)(3+/- sqrt (9+2536); sqrt(2545)=50.447 \n" ); document.write( "x=53.447/4 or 13.361 or 13.4 feet length \n" ); document.write( "and 23.724 feet width or 23.7 feet \n" ); document.write( "their product is 318.92 ft^2 \n" ); document.write( "using three decimal places, 13.361*23.724=316.98 ft^2 \n" ); document.write( " |