document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13784>Question 13784</A>: <I><SPAN STYLE=\"word-break: break-all;\"> here's my problem:  tickets for the homecoming dance cost $20 for a single ticket or $35 for a couple.  Ticket sales totaled $2280, and 128 people attended.  How many tickets of each type were sold?<BR>\n" );
document.write( "Here's what I've done so far:<BR>\n" );
document.write( "x+y=128  where x=# of single tickets and y=# of couple tickets<BR>\n" );
document.write( "20x+35y=2280   adding value to x and y equalling total dollars\r<BR>\n" );
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document.write( "have I set up the problem correctly?  I wasn't sure about the 128 in the first equation </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6911 by </B><A HREF=/tutors/aboutme.mpl?userid=glabow><B>glabow(165)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=glabow><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> No, you have a simple error. If y is the number of tickets sold for couples, then 2y persons attend for those tickets. So, x + 2y = 128. Your equation for the dollar amount of x and y ticket sales is correct. <BR>\n" );
document.write( "Solve x + 2y = 128 and 20x + 35y = 2280.<BR>\n" );
document.write( "[I got x=16 and y=56]<BR>\n" );
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