document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1076397>Question 1076397</A>: <I><SPAN STYLE=\"word-break: break-all;\"> moe can paddle his kayak 6 mph in still water. It takes him the same amount if time to paddle against the current for 5 miles as it does to paddle 10 miles with the current. How fast is the current in that section of the river </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691034 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691034\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let c be the speed of the current. Then:<BR>\n" );
document.write( "5/6-c = 10/6+c<BR>\n" );
document.write( "60-10c=30+5c<BR>\n" );
document.write( "15c=30<BR>\n" );
document.write( "c=2 mph as the speed of the current. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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