document.write( "Question 1076301: The police department is keeping track of distracted drivers and accidents. They have found that if a driver is distracted, the driver has a 30% chance of being in an accident. If the driver is not distracted, the driver has a 2% chance of being in an accident. The probability of a driver being distracted is 10%. If needed, create a tree diagram on a separate piece of paper. Then use the diagram to answer the questions. a. What is the probability a driver will be in an accident? Explain. b. What is the probability that a driver who was in an accident was distracted? Explain \n" ); document.write( "

Algebra.Com's Answer #691018 by Boreal(15235) $\"\"$ $\"About$

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======D=======ND====Total
\n" ); document.write( "A------30----------18------48
\n" ); document.write( "NA-----70---------882----952
\n" ); document.write( "Total==100======900===1000
\n" ); document.write( "Probability a driver will be in an accident is 48/1000 or 4.8%. This can be read right off the table, which has 9 cells. We get the bottom three from the 10% probability a driver is distracted, and we get the top left from the distracted-accident, the center from non distracted-accident. The rest can be filled in
\n" ); document.write( "If the driver was in an accident, the probability that they were distracted is 30/48 or 0.625. \n" ); document.write( "

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