document.write( "Question 1076338: A random sample of 700 workers in a particular city found 168 workers who had donated to charity. Find a 95% confidence interval for the true percent of workers in this city who have donated to charity.
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document.write( "Express your results as percents. Round to at least two decimal places. \n" );
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Algebra.Com's Answer #690994 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 95% CI is 0.24+/- 1.96 * sqrt (0.24*0.76)/168; the half interval is 0.032 \n" ); document.write( "(0.208, 0.272) \n" ); document.write( "The 0.24 comes from the fraction 168/700. \n" ); document.write( " |