document.write( "Question 94923: sinx + cosx - sinxcosx = sin^2 x + cos^2 x \n" ); document.write( "

Algebra.Com's Answer #69098 by Nate(3500) $\"\"$ $\"About$

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sinx + cosx - sinxcosx = sin^2 x + cos^2 x
\n" ); document.write( "cosx + sinx - sinxcosx = 1
\n" ); document.write( "cosx + sinx = 1 + sinxcosx
\n" ); document.write( "cos^2 x + 2cosxsinx + sin^2 x = 1 + 2sinxcosx + sin^2 x cos^2 x
\n" ); document.write( "cos^2 x + sin^2 x = 1 + sin^2 x cos^2 x
\n" ); document.write( "1 = 1 + sin^2 x cos^2 x
\n" ); document.write( "0 = sin^2 x cos^2 x
\n" ); document.write( "sin^2 x = 0
\n" ); document.write( "Ans: 2(pi)k
\n" ); document.write( "cos^2 x = 0
\n" ); document.write( "Ans: (pi)/2 + 2(pi)k
\n" ); document.write( "~k is any integer
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