document.write( "Question 1076286: I am developing a game where a result of 6 or more equals a Hit. I am stuck trying to find a formula for throwing multiple dice and scoring Hits on a sum of 6 or more e.g. for 1 die the answer is 1, for 2 dice it is 26 (?). Add a third dice or more and I am lost. Can anyone help please? Neil \n" ); document.write( "
Algebra.Com's Answer #690952 by Fombitz(32388)\"\" \"About 
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Yes, one die has one outcome.
\n" ); document.write( "Yes, two dice has 26 outcomes greater than or equal to 6.
\n" ); document.write( "Moving forward look at the 10 outcomes that are less than 6.
\n" ); document.write( "(1,1)=2
\n" ); document.write( "(1,2)=3
\n" ); document.write( "(1,3)=4
\n" ); document.write( "(1,4)=5
\n" ); document.write( "(2,1)=3
\n" ); document.write( "(2,2)=4
\n" ); document.write( "(2,3)=5
\n" ); document.write( "(3,1)=4
\n" ); document.write( "(3,2)=5
\n" ); document.write( "(4,1)=5
\n" ); document.write( "Now when you add the third dice you'll have a total of \"6%5E3\" or \"216\" possible outcomes.
\n" ); document.write( "Look for the ten outcomes and for each value of the die see if it is still below six.
\n" ); document.write( "Any sums of 5 will be eliminated.
\n" ); document.write( "Any sums at 2 will still be under six for 1,2,and 3.
\n" ); document.write( "Any sums at 3 will still be under six for 1 and 2.
\n" ); document.write( "Any sums at 4 will still be under six for 1.
\n" ); document.write( "So adding the new die value as the first variable,
\n" ); document.write( "Sums of 2 getting updated to (using 1,2,3),
\n" ); document.write( "(1,1,1)
\n" ); document.write( "(2,1,1)
\n" ); document.write( "(3,1,1)
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "Sums of 3 getting updated to (using 1,2),
\n" ); document.write( "(1,1,2)
\n" ); document.write( "(2,1,2)
\n" ); document.write( "(1,2,1)
\n" ); document.write( "(2,2,1)
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "Sums of 4 getting updated to (using 1),
\n" ); document.write( "(1,1,3)
\n" ); document.write( "(1,2,2)
\n" ); document.write( "(1,3,1)
\n" ); document.write( "So that makes 10 outcomes out of 216 still under six.
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