document.write( "Question 94915: How many gallons of a 60% solution must be mixed with 60 gallons of 40% solution to obtain a 50% solution? \r
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document.write( " 60 + y = t
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document.write( "( 40% of 60) + ( 60% of y ) = 50% of t\r
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document.write( "60 + y = t
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document.write( " 40( 60) 60y = ( 50)t\r
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document.write( "y = 60
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document.write( "t = 120\r
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document.write( "60 + 60= 120
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document.write( " 40% of 60+ 60% of 60 = 50% of 120\r
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Algebra.Com's Answer #69091 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! What is your question? \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |