document.write( "Question 1076156: In mixing a weed-killing solution, a 35% solution of the chemical is mixed with a 90% solution to get 55 L of a 60% solution. How much of each solution is needed. How many liters of the 35% solution is needed in the mixture? \n" ); document.write( "

Algebra.Com's Answer #690883 by jorel1380(3719) $\"\"$ $\"About$

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Let n be the amount of 35% solution. Then the amount of 90% solution would be 55-n. So:
\n" ); document.write( ".35n+.9(55-n)=.6(55)
\n" ); document.write( "49.5-0.55n=33
\n" ); document.write( "0.55n=16.5
\n" ); document.write( "n=30
\n" ); document.write( "You need 30L of 35% solution; and 25L of 90% solution. ☺☺☺☺ \n" ); document.write( "

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