document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=94916>Question 94916</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The mean of 21 test score is 78. What mean score must three additional students acheive so that the mean for all 24 students is 80.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69088 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mean of 21 test scores is 78. What mean score must three additional students achieve so that the mean for all 24 students is 80.<BR>\n" );
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document.write( "Let x be the mean of he three additional students.<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "(21*78 + 3x)/24 = 80<BR>\n" );
document.write( "21*78 + 3x = 1920<BR>\n" );
document.write( "1638 + 3x = 1920<BR>\n" );
document.write( "3x = 282<BR>\n" );
document.write( "x = 94 (average needed on the last 3 tests)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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