document.write( "Question 1075937: It is well known that (a/b)+(c/d) is not equivalent to (a+c)/(b+d).
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document.write( "Suppose that a, b, c, and d are all positive. Show that (a+c)/(b+d) is
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document.write( "in fact between the numbers a/b and c/d, while (a/b)+(c/d) is not \n" );
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Algebra.Com's Answer #690772 by Edwin McCravy(20055)  You can put this solution on YOUR website! It is well known that (a/b)+(c/d) is not equivalent to (a+c)/(b+d). \n" );
document.write( "Suppose that a, b, c, and d are all positive. \r \n" );
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document.write( "Show that (a+c)/(b+d) is in fact between the numbers a/b and c/d \n" );
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document.write( "Case 1. \r\n" );
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document.write( "Multiply through by LCD b(b+d)\r\n" );
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document.write( "Subtract ab from both sides\r\n" );
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document.write( "Add cd to both sides\r\n" );
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document.write( "Factor out d on left, c on right\r\n" );
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document.write( "Divide both sides by d(b+d)\r\n" );
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document.write( "So \r\n" );
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document.write( "Case 2. \r\n" );
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document.write( "Multiply through by LCD b(b+d)\r\n" );
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document.write( " \r\n" );
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document.write( "Subtract ab from both sides\r\n" );
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document.write( "Add cd to both sides\r\n" );
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document.write( "Factor out d on left, c on right\r\n" );
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document.write( "Divide both sides by d(b+d)\r\n" );
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document.write( "So \r\n" );
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document.write( "In either case, is between and \r\n" );
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document.write( "---------------------------------\r\n" );
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document.write( " is not between the numbers and \r\n" );
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document.write( "because the sum of two positive numbers is greater than\r\n" );
document.write( "either one.\r\n" );
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document.write( "Edwin \n" );
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