document.write( "Question 1076070: Shauna had an English average of 84%. On her next test she scored 96%, and this raised her overall average to 86%. On the test after this, her average fell to 85%. What was her mark on the last test \n" ); document.write( "
Algebra.Com's Answer #690765 by jorel1380(3719) You can put this solution on YOUR website! Let n be the number of tests Shauna has taken. Then: \n" ); document.write( "84n+96=86(n+1) \n" ); document.write( "2n=96-86=10 \n" ); document.write( "n=5 \n" ); document.write( "Let m be the score on her last test. Then: \n" ); document.write( "5*86+m=85*6 \n" ); document.write( "430+m=510 \n" ); document.write( "m=80 as her mark on the last test. ☺☺☺☺ \n" ); document.write( " |