document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1075676>Question 1075676</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to find the Z score that lies between z and -z, that contains 73% of the data under a normal distribution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #690740 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=690740\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 73% is under the curve then (100-73=27)% is in the left and right tail equally distributed.<BR>\n" );
document.write( "So then find the z score, so that <BR>\n" );
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