document.write( "Question 1075942: Find the equation of the median-median line for the data.\r
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document.write( "My three points are (500, 524), (2071, 782.5), and (5660, 2330) \r
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document.write( "Somehow I have come up with the same equation for Line A and Line B, and then again for the median-median line.\r
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document.write( "y = 0.35x + 349\r
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document.write( "Am I doing something incorrectly and if so, what is it? \n" );
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Algebra.Com's Answer #690597 by rothauserc(4718) You can put this solution on YOUR website! Label the three points m1, m2, m3 then \n" ); document.write( ": \n" ); document.write( "m1 is (500, 524), m2 is (2071, 782.5) and m3 is (5660, 2330) \n" ); document.write( ": \n" ); document.write( "start with the slope of the line through m1 and m3 \n" ); document.write( ": \n" ); document.write( "slope(m1-m3) = (2330 - 524) / (5660 - 500) = 0.35 \n" ); document.write( ": \n" ); document.write( "y(m1-m3) = 524 +(0.35)(x-500) \n" ); document.write( "y(m1-m3) = 0.35x +349 \n" ); document.write( ": \n" ); document.write( "y(m2) = 782.5 +(0.35)(x-2071) \n" ); document.write( "y(m2) = 0.35x +57.65 \n" ); document.write( ": \n" ); document.write( "The median-median line is parallel to y(m1-m3) and y(m2) so it will have the same slope(0.35). \n" ); document.write( ": \n" ); document.write( "To find the y-intercept of the median-median line, we find the mean of the y-intercepts of the lines through M1, M2, and M3. Since there is one line that passes through M1 and M3, the y-intercept for these lines are both 349. The y-intercept of the line through M2 is 57.65. \n" ); document.write( ": \n" ); document.write( "The mean of the y-intercepts is (349 +349 +57.65) / 3 = 251.8833 \n" ); document.write( ": \n" ); document.write( "********************************** \n" ); document.write( "y(median-median) = 0.35x +251.8833 \n" ); document.write( "********************************** \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |