document.write( "Question 1075902: the length of a rectangular plot of land with an area of 880 meters is 24 meters more than its width. If w represents the width of the plot of land in meters, write an equation in the form x^2+bx+c=0 that will be used to find the possible values if the width of the land \n" ); document.write( "

Algebra.Com's Answer #690556 by ikleyn(52787) $\"\"$ $\"About$

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document.write( "Let \"x\" be the value of the mid-point between L and W:  x = w + 12.\r\n" );
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document.write( "Then the width W = x - 12, while the length is L = x + 12.\r\n" );
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document.write( "WL = 880 then becomes (x-12)*(x+12) = 880,   or x^2 - 144 = 880.\r\n" );
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document.write( "Then x^2 = 880 + 144 = 1024,  and  x =  = 32.\r\n" );
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document.write( "Therefore, W = 32 - 12 = 20 and L = 32 + 12 = 44.\r\n" );
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document.write( "Answer.  The dimensions of the rectangle are 44 m  and  20 m.\r\n" );
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