document.write( "Question 1075831: A container holds 15 pennies, 8 nickels, and 10 dimes.
\n" ); document.write( "You will randomly select two coins without replacement.
\n" ); document.write( "-->Fill in the probabilities on a tree diagram.
\n" ); document.write( " --> How many ways can you select the coins?
\n" ); document.write( " --> How many ways can you select exactly 1 nickel?
\n" ); document.write( " --> What is the probability that you select 2 pennies?
\n" ); document.write( " --> What is the probability that you select a dime and then a penny?\r
\n" ); document.write( "\n" ); document.write( "I'm not sure if my answers are correct. I got 33 possible ways to select the coins.
\n" ); document.write( "8 out of 33 ways to select exactly one nickel.
\n" ); document.write( "35/176 probability that two pennies will be selected.
\n" ); document.write( "25/176 probability that a dime and a penny are selected.
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Algebra.Com's Answer #690540 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
A container holds 15 pennies, 8 nickels, and 10 dimes.
\n" ); document.write( "You will randomly select two coins without replacement.
\n" ); document.write( "-->Fill in the probabilities on a tree diagram.
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document.write( "Here's the probability tree:\r\n" );
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document.write( "There are 9 outcomes.  The probability of each outcome\r\n" );
document.write( "is gotten by multiplying the probabilities along the two\r\n" );
document.write( "lines from the beginning of the tree to the outcome.\r\n" );
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document.write( "For outcome #1, prob = (15/33)(14/32) which reduces to 35/176\r\n" );
document.write( "For outcome #2, prob = (15/33)(8/32) which reduces to 5/44\r\n" );
document.write( "For outcome #3, prob = (15/33)(10/32) which reduces to 25/176\r\n" );
document.write( "For outcome #4, prob = (8/33)(15/32) which reduces to 5/44\r\n" );
document.write( "For outcome #5, prob = (8/33)(7/32) which reduces to 7/132\r\n" );
document.write( "For outcome #6, prob = (8/33)(10/32) which reduces to 5/66\r\n" );
document.write( "For outcome #7, prob = (10/33)(15/32) which reduces to 25/176\r\n" );
document.write( "For outcome #8, prob = (10/33)(8/32) which reduces to 5/66\r\n" );
document.write( "For outcome #9, prob = (10/33)(9/32) which reduces to 15/176\r\n" );
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\r
\n" ); document.write( "\n" ); document.write( " --> How many ways can you select the coins?
There are 9 outcomes

\n" ); document.write( " --> How many ways can you select exactly 1 nickel?
That's either outcome #2, #4, #6, or #8, that's 4 ways

\n" ); document.write( " --> What is the probability that you select 2 pennies?
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document.write( "That's outcome #1, probability = 35/176

\n" ); document.write( " --> What is the probability that you select a dime and then a penny?
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document.write( "That's outcome #7, probability = 25/176\r\n" );
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document.write( "You got the hardest two right, and missed the two easy ones. lol\r\n" );
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document.write( "Edwin
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