document.write( "Question 1075860: please help me solve this
\n" ); document.write( "using substitution y=3^X, solve the equation 3^x=2+3^-x. \n" ); document.write( "

Algebra.Com's Answer #690503 by ikleyn(52790) $\"\"$ $\"About$

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\n" ); document.write( "O, great !!! This is entirely different and fully correct request.\r
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document.write( "After substituting  y = , your equation becomes\r\n" );
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document.write( "y = \r\n" );
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document.write( "Multiply by \"y\" both sides. You will get\r\n" );
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document.write( " = ,  or\r\n" );
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document.write( " = 0.\r\n" );
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document.write( "Apply the quadratic formula to solve the quadratic equation. You will get\r\n" );
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document.write( " =  =  = .\r\n" );
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document.write( "The negative root does not make sense, since y =  must be positive. \r\n" );
document.write( "It is EXTRANEOUS root for our problem.\r\n" );
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document.write( "The only positive root y =  survives.\r\n" );
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document.write( "So, we have  = , which implies\r\n" );
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document.write( "x = .\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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