document.write( "Question 1075730: Find one pair of real numbers, (x,y), such that x + y = 6 and x^3 + y^3 = 144.
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Algebra.Com's Answer #690413 by ikleyn(52786)\"\" \"About 
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document.write( "\"x%5E3+%2B+y%5E3\" = \"144\"\r\n" );
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document.write( "is equivalent to\r\n" );
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document.write( "\"%28x%2By%29%2A%28x%5E2+-+xy+%2B+y%5E2%29\" = \"144\".\r\n" );
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document.write( "Replace here (x+y) by 6 (due to the first equation) and cancel both sides by the factor of 6. You will get \r\n" );
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document.write( "\"x%5E2+-+xy+%2B+y%5E2\" = \"24\".\r\n" );
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document.write( "Now, from the first equation express x = 6-y and substitute it into the last equation. You will get\r\n" );
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document.write( "\"%286-y%29%5E2+-%286-y%29%2Ay+%2B+y%5E2\" = 24.\r\n" );
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document.write( "Simplify and solve this quadratic equation.\r\n" );
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