document.write( "Question 94855: 16.
\n" ); document.write( "Given the equation y=6-1/2x complete the table\r
\n" ); document.write( "\n" ); document.write( "-2 Blank
\n" ); document.write( " 0 Blank
\n" ); document.write( " 3 Blank\r
\n" ); document.write( "\n" ); document.write( "Can you help me please?
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Algebra.Com's Answer #69041 by hard(12)\"\" \"About 
You can put this solution on YOUR website!
Assuming that this a table of values, the work is as follows.
\n" ); document.write( "In this problem, you will just be inserting the numbers {-2, 0, and 3} into the x spot of the equation.
\n" ); document.write( "So:
\n" ); document.write( "y = 6 - 1/2(-2)
\n" ); document.write( "y = 6 + 1 (which is equiavlent to y = 6 - -1, because double negatives equal a positive!)
\n" ); document.write( "y = 7
\n" ); document.write( "So, 7 goes in the first blank, next to -2.
\n" ); document.write( "y = 6 - 1/2(0)
\n" ); document.write( "y = 6 - 0
\n" ); document.write( "y = 6
\n" ); document.write( "So, 6 goes in the second blank, next to 0.
\n" ); document.write( "y = 6 - 1/2(3)
\n" ); document.write( "y = 6 - 1.5
\n" ); document.write( "y = 4.5
\n" ); document.write( "So, 4.5, or 4 1/2, goes in the third blank, next to 3.
\n" ); document.write( "Remember to always check your answers after you finish a problem to make sure they're correct! It's better to take that extra time than to get them wrong on an assignment or test! Good luck!
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