document.write( "Question 1075760: A bulldozer was purchased by a construction company for $224,000 and has a depreciated value of $100,000 after 8 years. If the value is depreciated linearly from $224,000 to $100,000,
\n" ); document.write( "(A) Find the linear equation that relates value V (in dollars) to time t (in years).
\n" ); document.write( "(B) What would be the depreciated value after 12 years?\r
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Algebra.Com's Answer #690392 by Boreal(15235)\"\" \"About 
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It has depreciated 124000 in 8 years, which is $15,500 per year.\r
\n" ); document.write( "\n" ); document.write( "at 0 years (y-intercept), the value was $224,000\r
\n" ); document.write( "\n" ); document.write( "The equation is y=224000-15500x.
\n" ); document.write( "After 12 years, because 15,500*12=186,000, the value is $224,000-$186,000=$38,000.
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