document.write( "Question 1075689: Please help me solve this problem : Find the value of the constant k such that the ratio of the two
\n" ); document.write( "solution of the quadratic equation 2x2 - kx+ k +2 = 0 is 3:2
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Algebra.Com's Answer #690351 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let \"a\" be one solution of the given equation  \"2x%5E2+-+kx%2B+k+%2B2\" = \"0\".\r\n" );
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document.write( "Then the other solution is \"%283%2F2%29%2Aa\".\r\n" );
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document.write( "If so, then the given polynomial \"2x%5E2+-+kx%2B+k+%2B2\" admits factorization\r\n" );
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document.write( "\"2x%5E2+-+kx%2B+k+%2B2\" = \"2%2A%28x-a%29%2A%28x-%283%2F2%29a%29\" = (x-a)*(2x-3a) = \"2x%5E2+-+5ax+%2B+3a%5E2\".\r\n" );
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document.write( "It means that  -k = -5a, 3a^2 = k+2,   or  (substituting)\r\n" );
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document.write( "\"5a+%2B+2\" = \"3a%5E2\",\r\n" );
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document.write( "\"3a%5E2+-+5a+%2B2\" = 0  --->  \"a%5B1%2C2%5D\" = \"%285+%2B-+sqrt%2825+-+4%2A3%2A2%29%29%2F%282%2A3%29\" = \"%285+%2B-+1%29%2F6\".\r\n" );
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document.write( "1.  \"a%5B1%5D\" = \"5%2B1%29%2F6\" = 1  ---->  k = 5a = 5;\r\n" );
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document.write( "2.  \"a%5B2%5D\" = \"%285-1%29%2F6\" = \"4%2F6\" = \"2%2F3\".  ---->  k = 5a = \"10%2F3\".\r\n" );
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document.write( "Answer.  There are TWO solutions for k:  1) k = 5,   and   2)  k = \"10%2F3\".\r\n" );
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