document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1075418>Question 1075418</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the EXACT value.\r<BR>\n" );
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document.write( "1. sin (-5pi/12)\r<BR>\n" );
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document.write( "2. 2 sin (2 angle)=1\r<BR>\n" );
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document.write( "Thanks for the help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #690287 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=690287\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sin -5pi/12=sin of 19 pi/12 as well.<BR>\n" );
document.write( "This is sin (10pi/12+9pi/12)<BR>\n" );
document.write( "=sin(10pi/12)*cos(9pi/12)+cos(10pi/12)*sin(9pi/12)<BR>\n" );
document.write( "both of these are negative<BR>\n" );
document.write( ".5*(-sqrt(2)/2)+(-sqrt(3)/2*sqrt(2)/2)=<BR>\n" );
document.write( "sqrt(2)/4+sqrt(6)/4<BR>\n" );
document.write( "(1/4)(sqrt(2)+sqrt(6))<BR>\n" );
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document.write( "This is sin (2A)=1/2<BR>\n" );
document.write( "I know that pi/6 radians gives a sin of 1/2<BR>\n" );
document.write( "Therefore, A must be pi/12 radians.<BR>\n" );
document.write( "One can check by sin 2A=2sin A cos A =1/2<BR>\n" );
document.write( "sinA cos A=1/4<BR>\n" );
document.write( "If one uses pi/6 for A or 15 degrees, this will work.<BR>\n" );
document.write( "Answer is pi/6 radians. </SPAN>\n" );
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