document.write( "Question 1075443: Women have pulse rates that are normally distributed with a mean of
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document.write( "80.280.2
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document.write( "beats per minute and a standard deviation of
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document.write( "10.910.9
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document.write( "beats per minute. Complete parts a through c below.\r
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document.write( "a. Find the percentiles
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document.write( "Upper P 1P1
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document.write( "and
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document.write( "Upper P 99P99. \n" );
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Algebra.Com's Answer #690262 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The 1% percentile is z=-2.328, the 99th z=+2.328 \n" ); document.write( "z*sd=2.328*10.910=25.398 \n" ); document.write( "lower is 54.882 bpm \n" ); document.write( "upper is 105.678 bpm \n" ); document.write( " |