document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1075604>Question 1075604</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You roll dice twice.  Find the probability of the compound event \"The first roll was even AND the second roll was larger than 4\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #690242 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=690242\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two ways to interpret this problem.<BR>\n" );
document.write( "One die rolled twice: (1/2) probability even* (1/3) larger than 4 (5 and 6)=1/6 total probability.<BR>\n" );
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document.write( "Two dice (because plural form of noun die).<BR>\n" );
document.write( "First roll is even<BR>\n" );
document.write( "That occurs when 2,4,6,8,10,12, and that is (1/2) as well but second part, greater than 4 is 30/36 or 5/6.  That joint probability is (1/2)*(5/6)=(5/12)<BR>\n" );
document.write( "I suspect the first solution is what is asked for. </SPAN>\n" );
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