document.write( "Question 1075576: The expression cot thita (tan thita+sin thita) wherever defined, simplifies to
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #690225 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "It's \"theta\", not \"thita\", pronounced \"THAY-tuh\"\r\n" );
document.write( "\r\n" );
document.write( "\"cot%28theta%29%28tan%28theta%29%5E%22%22%2Bsin%28theta%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"cot%28theta%29tan%28theta%29%2Bcot%28theta%29sin%28theta%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "Use the two identities for the cotangent:\r\n" );
document.write( "       \"cot%28theta%29=1%2Ftan%28theta%29\" and \"cot%28theta%29=cos%28theta%29%2Fsin%28theta%29\"\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\"1%2Bcos%28theta%29\"\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );