document.write( "Question 94739This question is from textbook Introductory algebra
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document.write( ": A triangular region has a perimeter of 66 meters. The first side is two-thirds of the second side. The third side is 14 meters shorter than the second side. What are the lengths of the three sides of the triangular region? \n" );
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Algebra.Com's Answer #69021 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let x = length of the 2nd side \n" ); document.write( ": \n" ); document.write( "It says,\" The first side is two-thirds of the second side.\" Therefore: \n" ); document.write( "1st side = 2x/3 \n" ); document.write( ": \n" ); document.write( "It also says,\"The third side is 14 meters shorter than the second side.\" Therefore: \n" ); document.write( "3rd side = (x-14) \n" ); document.write( ": \n" ); document.write( "What are the lengths of the three sides of the triangular region? \n" ); document.write( "It says \"A triangular region has a perimeter of 66 meters.\" Therefore: \n" ); document.write( ": \n" ); document.write( "side 1 + side 2 + side 3 = 66 \n" ); document.write( "(2x/3) + x + (x-14) = 66 \n" ); document.write( ": \n" ); document.write( "Multiply equation by 3 to get rid of the denominator: \n" ); document.write( "2x + 3x + 3(x-14) = 3(66) \n" ); document.write( "2x + 3x + 3x - 42 = 198 \n" ); document.write( " 8x = 198 + 42 \n" ); document.write( " 8x = 240 \n" ); document.write( " x = 240/8 \n" ); document.write( " x = 30 m, the length of side 2 \n" ); document.write( ": \n" ); document.write( "2/3(30) = 20 m, the length of side 1 \n" ); document.write( ": \n" ); document.write( "30 - 14 = 16m, the length of side 3 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution, using the perimeter: \n" ); document.write( "20 + 16 + 30 = 66 \n" ); document.write( " |