document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1075535>Question 1075535</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the series -7,-4,-1,2,... using summation notation\r<BR>\n" );
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document.write( "Thank you:) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #690186 by </B><A HREF=/tutors/aboutme.mpl?userid=Lightning_Fast><B>Lightning_Fast(78)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Lightning_Fast><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Lightning_Fast><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=690186\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">   <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/display-illustration.mpl?tutor=Lightning_Fast&illustration_name=1075535\">.\r<BR>\n" );
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document.write( "Starts at one. End behavior is positive so the coefficient of x must be positive. Initially negative so find the value where x=1 such that the result is -7. The value was 10. </SPAN>\n" );
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