document.write( "Question 1075548: Solve:\r
\n" ); document.write( "\n" ); document.write( "Log5(2x+1)+Log5(x+2)=1 \n" ); document.write( "

Algebra.Com's Answer #690180 by Lightning_Fast(78) $\"\"$ $\"About$

You can put this solution on YOUR website!
Remember the log rule
\n" ); document.write( " $\"logx%283%29%2Blogx%284%29=log%283%2A4%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Thus
\n" ); document.write( " $\"log5%282x%2B1%29%2Blog5%28x%2B2%29=1\"$
\n" ); document.write( " $\"log5%282x%5E2%2B4x%2Bx%2B2%29=1\"$
\n" ); document.write( " $\"5%5E1=2x%5E2%2B5x%2B2\"$
\n" ); document.write( "Now just factor and solve from x there. Hope this helped. \n" ); document.write( "

\n" );