document.write( "Question 1075464: If the zeroes of the quadratic polynomials x^2+(a+1)x+b are 2 and -3,then find the values of a and b\r
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Algebra.Com's Answer #690134 by ikleyn(52810) $\"\"$ $\"About$

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\n" ); document.write( "If the zeroes of the quadratic $\"highlight%28cross%28polynomials%29%29\"$ polynomial x^2+(a+1)x+b are 2 and -3,then find the values of a and b
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\n" ); document.write( "\n" ); document.write( "Use the Vieta's theorem\"\r
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document.write( "    The sum of roots of a quadratic polynomial is equal to the coefficient at x with the opposite sign;\r\n" );
document.write( "    The product of the roots is equal to the constant term.\r\n" );
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\n" ); document.write( "\n" ); document.write( "In your case it gives b = 2*(-3) = -6.\r
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\n" ); document.write( "\n" ); document.write( "a+1 = -(2 + (-3)) = -(-1) = 1; hence, a = 0.\r
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\n" ); document.write( "\n" ); document.write( "Answer. a = 0; b = -6.\r
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