document.write( "Question 1075496: The hypotenuse of a right triangle is 7 less than three times the shortest leg. The longer of the two legs is 7 more than the shorter leg. Find all three missing lengths.\r
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Algebra.Com's Answer #690129 by ikleyn(52781)\"\" \"About 
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document.write( "The Pythagorean equation in this case is \r\n" );
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document.write( "\"x%5E2+%2B+%28x%2B7%29%5E2\" = \"%283x-7%29%5E2\"\r\n" );
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document.write( "where x is the length of the shortest leg.\r\n" );
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document.write( "\"x%5E2+%2B+x%5E2+%2B+14x+%2B+49\" = \"9x%5E2+-+42x+%2B+49\"\r\n" );
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document.write( "\"7x%5E2++-+56x\" = 0.\r\n" );
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document.write( "(x - 8)x = 0-,\r\n" );
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document.write( "x = 8 is the only admittable solution.\r\n" );
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document.write( "Answer.  The side lengths of the triangle are 8, 15 and 17 units.\r\n" );
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