document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1075453>Question 1075453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr. Bondi is replacing the square tiles in his bathroom.  Each new tile is 3 inches longer and 3 inches wider than an old tile.  Each new tile covers 39 square inches more than an old tile.\r<BR>\n" );
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document.write( "A)  How big were the old tiles? ____ inches  by ____ inches\r<BR>\n" );
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document.write( "B)  If the area of a room is 5120 square inches, how many new tiles will he need?  _____ tiles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #690120 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=690120\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let l be the length of the old tile and w be the width of the old tile, then<BR>\n" );
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document.write( "The area of the new tile minus the area of the old tile equals 39<BR>\n" );
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document.write( "(l+3)(w+3) -lw = 39<BR>\n" );
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document.write( "lw +3l +3w +9 -lw = 39<BR>\n" );
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document.write( "3l +3w = 30<BR>\n" );
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document.write( "l +w = 10<BR>\n" );
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document.write( "We know that the area of the old tile is maximized when l = 5 and w = 5<BR>\n" );
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document.write( "A) 5 inches by 5 inches<BR>\n" );
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document.write( "B) The area of a new tile is (5+3)(5+3) = 64 square inches<BR>\n" );
document.write( "Note that 25 + 39 = 64<BR>\n" );
document.write( "5120 / 64 = 80 new tiles<BR>\n" );
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