document.write( "Question 94746This question is from textbook
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document.write( ": A wallet contains $5 bills and $10 bills. There are 15 bills in the wallet with a total value of $120. Determine the number of $5bills and the number of $10 bills in the wallet. \n" );
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Algebra.Com's Answer #69003 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=number of $5 bills\r \n" ); document.write( "\n" ); document.write( "Then 15-x=number of $10 bills\r \n" ); document.write( "\n" ); document.write( "Now we are told that: (dollars are understood) \n" ); document.write( "5x+10(15-x)=120 get rid of parens\r \n" ); document.write( "\n" ); document.write( "5x+150-10x=120 subtract 150 from both sides\r \n" ); document.write( "\n" ); document.write( "5x+150-150-10x=120-150 collect like terms \n" ); document.write( "-5x=-30 divide both sides by -5\r \n" ); document.write( "\n" ); document.write( "x=6----------------number of $5 bills \n" ); document.write( "15-6=9----------------number of $10 bills\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "6*5+10*9=120 \n" ); document.write( "30+90=120 \n" ); document.write( "120=120\r \n" ); document.write( "\n" ); document.write( "Another way:\r \n" ); document.write( "\n" ); document.write( "x=number of $5 \n" ); document.write( "y=number of $10\r \n" ); document.write( "\n" ); document.write( "x+y=15--------------------eq1 \n" ); document.write( "5x+10y=120-------------------eq2 \n" ); document.write( "Notice that if we substituted y=15-x from eq1 into eq2 we end up with the same equation that we initially solved\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps----------------ptaylor \n" ); document.write( " |