document.write( "Question 94746This question is from textbook
\n" ); document.write( ": A wallet contains $5 bills and $10 bills. There are 15 bills in the wallet with a total value of $120. Determine the number of $5bills and the number of $10 bills in the wallet. \n" ); document.write( "
Algebra.Com's Answer #69003 by ptaylor(2198)\"\" \"About 
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Let x=number of $5 bills\r
\n" ); document.write( "\n" ); document.write( "Then 15-x=number of $10 bills\r
\n" ); document.write( "\n" ); document.write( "Now we are told that: (dollars are understood)
\n" ); document.write( "5x+10(15-x)=120 get rid of parens\r
\n" ); document.write( "\n" ); document.write( "5x+150-10x=120 subtract 150 from both sides\r
\n" ); document.write( "\n" ); document.write( "5x+150-150-10x=120-150 collect like terms
\n" ); document.write( "-5x=-30 divide both sides by -5\r
\n" ); document.write( "\n" ); document.write( "x=6----------------number of $5 bills
\n" ); document.write( "15-6=9----------------number of $10 bills\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "6*5+10*9=120
\n" ); document.write( "30+90=120
\n" ); document.write( "120=120\r
\n" ); document.write( "\n" ); document.write( "Another way:\r
\n" ); document.write( "\n" ); document.write( "x=number of $5
\n" ); document.write( "y=number of $10\r
\n" ); document.write( "\n" ); document.write( "x+y=15--------------------eq1
\n" ); document.write( "5x+10y=120-------------------eq2
\n" ); document.write( "Notice that if we substituted y=15-x from eq1 into eq2 we end up with the same equation that we initially solved\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----------------ptaylor
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