document.write( "Question 1075351: How do u factor 12x^2+22x-14
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Algebra.Com's Answer #690023 by rothauserc(4718) You can put this solution on YOUR website! 12x^2 +22x -14 \n" ); document.write( ": \n" ); document.write( "since 12 > 0, we know that both factors are positive \n" ); document.write( ": \n" ); document.write( "factors of 12 are (12, 1) (6, 2) (4, 3) \n" ); document.write( ": \n" ); document.write( "since -14 < 0, we know that one of the factors is positive and other is negative \n" ); document.write( ": \n" ); document.write( "factors of 14 are (14, 1), (2, 7) \n" ); document.write( ": \n" ); document.write( "We try the factors of 12 one at a time with the three factors of 14 \n" ); document.write( ": \n" ); document.write( "Using this method, we find that \n" ); document.write( ": \n" ); document.write( "*********************************** \n" ); document.write( "(6x +14) * (2x -1) = 12x^2 +22x -14 \n" ); document.write( "*********************************** \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |