document.write( "Question 94760: How many gallons of a 40% solution must be mixed with 96 gallons of 60% solution to obtain a 52% solution? \n" ); document.write( "

Algebra.Com's Answer #69002 by ptaylor(2198) $\"\"$ $\"About$

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Let x=number of gal of 40% solution needed\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure liquid in the 40% solution (0.40x) plus the amount of pure liquid in the 60% solution (0.60*96) has to equal the amount of pure liquid in the final mixture(96+x)*0.52. So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.40x+(0.60*96)=0.52(96+x) get rid of parens\r
\n" ); document.write( "\n" ); document.write( "0.40x+57.6=49.92+0.52x subtract 0.52x and also 57.6 from both sides\r
\n" ); document.write( "\n" ); document.write( "0.40x-0.52x+57.6-57.6=49.92-57.6+0.52x-0.52x collect like terms\r
\n" ); document.write( "\n" ); document.write( "-0.12x=-7.68 divide both sides by -0.12\r
\n" ); document.write( "\n" ); document.write( "x=64-------------------------number of gal of 40% solution needed\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "0.40*64+0.60*96=0.52(96+64)
\n" ); document.write( "25.6+57.6=83.2
\n" ); document.write( "83.2=83.2\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps------ptaylor\r
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