document.write( "Question 1075322: Simplify and state restrictions\r
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Algebra.Com's Answer #690001 by Edwin McCravy(20064) $\"\"$ $\"About$

You can put this solution on YOUR website!
Simplify and state restrictions\r
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document.write( "We factor the denominator on the first fraction:\r\n" );
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document.write( "None of the denominators can be 0, so\r\n" );
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document.write( "we must restrict the denominators\r\n" );
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document.write( "n+8≠0,   n+3≠0\r\n" );
document.write( "  n≠-8,    n≠-3\r\n" );
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document.write( "However we must not divide by 0, so the numerator\r\n" );
document.write( "of what we are dividing by must not equal 0 either\r\n" );
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document.write( "So the numerator of the second fraction also cannot\r\n" );
document.write( "be 0, for then the fraction that we are dividing by\r\n" );
document.write( "would be 0, and we cannot divide by zero.\r\n" );
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document.write( "n+1≠0\r\n" );
document.write( "  n≠-1\r\n" );
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document.write( "So the restrictions are n≠-8, n≠-3, and n≠-1\r\n" );
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document.write( "To finish the problem, we invert the second fraction\r\n" );
document.write( "and multiply:\r\n" );
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document.write( "and cancel:\r\n" );
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document.write( ", n≠-8, n≠-3, n≠-1\r\n" );
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document.write( "Edwin

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