document.write( "Question 1075231: What is the first term of a sequence when the eighth term is twice the third term and the sum of the first eight terms is 39? \n" ); document.write( "
Algebra.Com's Answer #689930 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
a8=2a3
\n" ); document.write( "a1+a2+a3+a4+a5+a6+a7+a8=39
\n" ); document.write( "(8/2)(a1+a8)=39=4(a1+2a3)\r
\n" ); document.write( "\n" ); document.write( "a4=1.2a3
\n" ); document.write( "a5=1.4a3
\n" ); document.write( "a6=1.6a3
\n" ); document.write( "a7=1.8a3
\n" ); document.write( "a8=2a3
\n" ); document.write( "a3=a3
\n" ); document.write( "a2=0.8a3
\n" ); document.write( "a1=0.6a3
\n" ); document.write( "The sum, 39, equals 10.4 a3
\n" ); document.write( "Therefore, a3=3.75
\n" ); document.write( "a8=7.5
\n" ); document.write( "a1=2.25 ANSWER
\n" ); document.write( "sum=4*(a1+a8)=4(9.75)=39
\n" ); document.write( "
\n" ); document.write( "
\n" );