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A farmer has 160 yd of fencing material and wants to enclose three rectangular pens.
\n" ); document.write( " The farmer wants each pen to be 250 square yd.
\n" ); document.write( " What will be the dimensions of each pen?
\n" ); document.write( ":
\n" ); document.write( "Let w = the width, each side and the two which divide it into 3 ea 250 sq/yd fields
\n" ); document.write( "let L = the Length
\n" ); document.write( "Then
\n" ); document.write( "2L + 4w = 160
\n" ); document.write( "Simpify, divide by 2
\n" ); document.write( "L + 2w = 160
\n" ); document.write( "L = -2w + 160
\n" ); document.write( "Total area = 3(250) = 750 sq/yd
\n" ); document.write( "L * w = 750
\n" ); document.write( "replace L with (-2w+160)
\n" ); document.write( "w(-2w+160) = 750
\n" ); document.write( "-2w^2 + 160w - 750 = 0
\n" ); document.write( "simplify, divide by -2
\n" ); document.write( "w^2 = 80w + 375 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(w - 75)(w - 5) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "w = 75 yds
\n" ); document.write( "w = 5 yds, use this for width, (the other solution will work too)
\n" ); document.write( "find the length
\n" ); document.write( "L = -2(5) + 160
\n" ); document.write( "L = -10 + 160
\n" ); document.write( "L = 150 yds is the length
\n" ); document.write( ":
\n" ); document.write( "Confirm that we have 3 fields with 250 sq/yds, divide the length by 3
\n" ); document.write( "50 * 5 = 250 sq/yds \n" ); document.write( "