document.write( "Question 1075222: you have some nickles and some pennies totaling 52 cents.There are 19 coin in all.How many of each type do you have \n" ); document.write( "
Algebra.Com's Answer #689890 by Boreal(15235) You can put this solution on YOUR website! N+P=19 \n" ); document.write( ".05N+.01P=0.52 \n" ); document.write( "5N+P=52 \n" ); document.write( "-N-P=-19 \n" ); document.write( "4N=33 \n" ); document.write( "This can't be answered \n" ); document.write( "8 nickels and 11 pennies would be 51 cents \n" ); document.write( "7 nickels and 12 pennies would be 47 cents \n" ); document.write( "With 19 coins, only 12,17 can be pennies to make some number of cents ending in 2. \n" ); document.write( " \n" ); document.write( " |