document.write( "Question 1075209: Use a graphing utility, where helpful, to find the area of the region enclosed by the curves.\r
\n" ); document.write( "\n" ); document.write( "y=x^3−13x^2+30x and y=0.\r
\n" ); document.write( "\n" ); document.write( "Carry out all calculations exactly and round to 2 decimal places the final answer only. \n" ); document.write( "
Algebra.Com's Answer #689887 by Alan3354(69443)\"\" \"About 
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Use a graphing utility, where helpful, to find the area of the region enclosed by the curves.\r
\n" ); document.write( "\n" ); document.write( "y=x^3-13x^2+30x and y=0.
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\n" ); document.write( "y=x^3-13x^2+30x
\n" ); document.write( "INT = x^4/4 - 13x^3/3 + 15x^2 + C
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\n" ); document.write( "y = 0 is the x-axis
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\n" ); document.write( "There are 2 zeroes.
\n" ); document.write( "x = 3 and x = 10
\n" ); document.write( "The area from x = 0 to x = 3 is above the x-axis.
\n" ); document.write( "x^4/4 - 13x^3/3 + 15x^2 + C
\n" ); document.write( "f(0) = 0
\n" ); document.write( "f(3) = 81/4 - 117 + 135
\n" ); document.write( "f(3) - f(0) = 153/4 sq units
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\n" ); document.write( "The area from x=3 to x=10 is below the x-axis.
\n" ); document.write( "f(10) = 2500 - 13000/3 + 1500 = -1000/3
\n" ); document.write( "f(10) - f(3) = -4459/12 sq units
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\n" ); document.write( "IDK how you want to combine the two areas.\r
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