document.write( "Question 1075200: The corners of a piece of paper are cut to make an open top box. The cut corners are 0.5 in by 0.5 in. If the width of the paper is two-thirds the height what, what are the dimensions of the paper if the volume is to be 60 cubic inches? \n" ); document.write( "
Algebra.Com's Answer #689884 by stanbon(75887)\"\" \"About 
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The corners of a piece of paper are cut to make an open top box. The cut corners are 0.5 in by 0.5 in. If the width of the paper is two-thirds the height what, what are the dimensions of the paper if the volume is to be 60 cubic inches?
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\n" ); document.write( "width = (2/3)h inches
\n" ); document.write( "height = h inches
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\n" ); document.write( "After cutting the corners::
\n" ); document.write( "width = (2/3)h - 1 inches
\n" ); document.write( "height = h - 1 inches
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\n" ); document.write( "Volume Equation:
\n" ); document.write( "h(h-1)((2/3)h-1) = 60 cu in
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\n" ); document.write( "h((2/3)h^2 - (5/3)h + 1) = 60
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\n" ); document.write( "(2/3)h^3 - (5/3)h^2 + h - 60 = 0
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\n" ); document.write( "Take the derivative::
\n" ); document.write( "V'(h) = 2h^2 - (10/3)h + 1
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\n" ); document.write( "Solve V'(h) = 0
\n" ); document.write( "h = 1.274 inches (height of the paper)
\n" ); document.write( "(2/3)h = 0.523 inches (width of the paper)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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