document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1075195>Question 1075195</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 28) through 33) the heights of 1000 students in a college are normally distributed with a mean 5’10” and SD 2”. Use 68% for the region from the mean to 1-SD on either side; 94% for the region from the mean to 2-SD on either side and 98% for the region from the mean to 3-SD on either side. Find the approximate number of students in each range of the heights:\r<BR>\n" );
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document.write( "28) 5’8”–6’\r<BR>\n" );
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document.write( "29) 5’6”–6’2”\r<BR>\n" );
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document.write( "30) Above 5’10”\r<BR>\n" );
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document.write( "31) Below 6’\r<BR>\n" );
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document.write( "32) Above 5’8”\r<BR>\n" );
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document.write( "33) 5’8”–6’4”\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #689882 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=689882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 28) through 33) the heights of 1000 students in a college are normally distributed with a mean 5’10” and SD 2”. Use 68% for the region from the mean to 1-SD on either side; 94% for the region from the mean to 2-SD on either side and 98% for the region from the mean to 3-SD on either side. Find the approximate number of students in each range of the heights: <BR>\n" );
document.write( "28) 5’8”–6’<BR>\n" );
document.write( "z(5'8\") = (5'8\"-5'10\")/2\" = -2\"/2\" = -1C<BR>\n" );
document.write( "P(6\") = (6\"-5'10\")/2\" = 2\"/2\" = 1<BR>\n" );
document.write( "P(5'8 to 6') = P(-1<= z <=1) = 68% = 0.68<BR>\n" );
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document.write( "Comment:: Follow that Example and you should be able<BR>\n" );
document.write( "to find answers for your remaining problems.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "29) 5’6”–6’2” <BR>\n" );
document.write( "30) Above 5’10” <BR>\n" );
document.write( "31) Below 6’ <BR>\n" );
document.write( "32) Above 5’8” <BR>\n" );
document.write( "33) 5’8”–6’4”  </SPAN>\n" );
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