document.write( "Question 1075178: solve for (0,2pi)\r
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document.write( "4cos x+ 4cos^2 x+1=0\r
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Algebra.Com's Answer #689869 by ikleyn(52873) You can put this solution on YOUR website! . \n" ); document.write( "4cos x+ 4cos^2 x+1=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4cos^2 + 4cos + 1 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(2cos + 1)^2 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cos(x) = -1/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 2pi/3, 4pi/3\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The solution by other tutor is incorrect.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |