document.write( "Question 1075149: Please help me solve the following problem. I will appreciate your solution\r
\n" ); document.write( "\n" ); document.write( "The weight of a certain type of chicken, when ready for the market, follows a normal distribution with mean 1.0 kg and a standard deviation of 0.20 kg. Find the percentage of the chickens that weigh between 0.89 kg and 1.50 kg.
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Algebra.Com's Answer #689823 by Boreal(15235)\"\" \"About 
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This is finding the z-value
\n" ); document.write( "That is z=(x-mean)/sd
\n" ); document.write( "(0.89-1.0)/0.20=-0.11/0.20=-0.55
\n" ); document.write( "(1.5-1.0)/0.20=.5/.2=2.5
\n" ); document.write( "want the probability of z being between 0=-0.55 and 2.5
\n" ); document.write( "it is 0.7026.
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